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WebIn order to calculate the the internal inductance of a wire we have to equate the equation for the energy of the magnetic field to the energy from the inductor/inductance. Energy of the B field: 1 2μ∫ B2dV, where B is integrated over all space. Energy of an inductor: 1 2LI2 WebThe current density in a cylindrical wire of radius R = 3.0 mm is uniform across a cross section of the wire and is J = 1.5105 A/m2 (a) What is the current through the outer … http://teacher.pas.rochester.edu/phy122/Lecture_Notes/Chapter31/chapter31.html daisy and grace